I recently acquired a nice Adventurer and it needs just a little work. I will be replacing the cord for a three-prong variant and also need to balance a Cap replacement network. The fellow I bought it from did a neat install of new caps to replace C15 and C16. The Schematic and parts list (see below) list the caps as 8mfd 700 volts. As many of us do, the replacement was made up of lower voltage (450v) , higher capacitance (16 uf) electrolytic caps, as the 700v variants are hard to find I guess. My issue with the install, is that there are no balance resistors in the network. I'm a tinkerer and not an EE, but I do know that much. What I need help with is the watt rating, resistance and the arrangement of the resistors. I don't want to risk doing damage. I found this calculator: Here is the Cap Network installed in my Adventurer: Based on the formula above, I calculated 14.4M ohm resistors. I used 600 volts for the circuit voltage. A guess. The article that produced the formula I used, suggests that you could safely halve the resistance, so 7M ohms? But, what wattage resistor to use? I found the following photo, albeit incomplete work, of a balanced cap network in an adventurer. The same principal I'm attempting to replicate: These look like 150K ohm resistors and not exactly neat or complete, but it's the only Adventurer example I could find for this post. These look like 2 watt resistors? Here is the schematic and parts list if you are so inclined: So, if you know the answer, or are really bored and feel like elmering me on how to make this network safer, take a look and please let me know. I assume I merely parallel a resistor of the same value across each capacitor? The idea being to make each capacitor do equal work? Learning a ton and very grateful for all the help I get on this forum! Thanks.